Final answer:
The compounds are named as Iron(III) oxide, Copper(II) chloride, Tin(IV) fluoride, and Lead(IV) oxide, based on the charge of the metal ions which are Fe³⁺, Cu²⁺, Sn⁴⁺, and Pb⁴⁺ respectively.
Step-by-step explanation:
The question requires the proper naming of ionic compounds containing metals that can exhibit more than one ionic charge. In naming such compounds, it is important to determine the charge of the metal ion because these metals can exhibit multiple oxidation states.
The charge of the metal in the compound is typically indicated using Roman numerals in parentheses immediately following the name of the metal. Here are the names for the given compounds:
- Iron(III) oxide: Fe₂O₃
- Copper(II) chloride: CuCl₂
- Tin(IV) fluoride: SnF₄
- Lead(IV) oxide: PbO₂