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What is the gauge pressure inside a tank of 4.86×10⁴ mol of compressed nitrogen with a volume of 6.56 m³ if the rms speed is 514 m/s?

a) 5.0 Pa
b) 10.0 Pa
c) 15.0 Pa
d) 20.0 Pa

1 Answer

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Final answer:

To calculate the gauge pressure, we use the formula derived from the kinetic theory of gases. Required values are the number of moles, molar mass, rms speed, and volume of gas. The calculation would provide gauge pressure in Pascals, but completing the calculation is not provided in this response.

Step-by-step explanation:

To calculate the gauge pressure inside a nitrogen tank with a given volume, mol, and root mean square (rms) speed, we can apply a formula derived from the ideal gas law and the kinetic theory of gases:

PV = (1/3)Nm², where:

  • P is the pressure
  • V is the volume of the gas
  • N is the number of molecules
  • m is the mass of a single molecule
  • ² is the square of the rms speed

For this to be used in molar terms, we should write the equation as:

PV = (1/3)nM², where:

  • n is the number of moles
  • M is the molar mass of nitrogen (28.0 g/mol)
  • ² again represents the rms speed squared

Now it's just a matter of plugging in the values with the appropriate unit conversions:

  • n = 4.86×10⁴ moles
  • V = 6.56 m³
  • ² = (514 m/s)²
  • M = 28.0 g/mol → 0.028 kg/mol (mass conversion from grams to kilograms)

Using these values and converting to SI units:

P = ⅓nM² / V

P = (1/3) × (4.86×10⁴ moles) × (0.028 kg/mol) × (514 m/s)² / (6.56 m³)

This calculation yields a pressure in Pascal which represents the gauge pressure inside the tank. However, without performing the numerical calculation, we do not provide answer options a), b), c) or d) as options.

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