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One mole of a dilute diatomic gas occupying a volume of 10.00 L expands against a constant pressure of 2.000 atm when it is slowly heated. If 400.0 J of heat is added in the process, what is its final volume?

a) 12.00 L
b) 15.00 L
c) 18.00 L
d) 20.00 L

User SilentICE
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1 Answer

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Final answer:

To determine the final volume of a diatomic gas expanded at constant pressure, we use the work formula W = PΔV and the relation Q = W for constant pressure processes. We find that the final volume is approximately 12.00 L after adding 400 J of heat to the gas at a constant pressure of 2.000 atm.

Step-by-step explanation:

To find the final volume of a diatomic gas after it has been heated and expanded against a constant pressure, we can use the first law of thermodynamics, which states that the change in the internal energy of a system (ΔU) is equal to the heat added to the system (Q) minus the work done by the system (W).

For a constant pressure process, work done by the gas, W, is given by:

W = P ΔV

where P is the pressure and ΔV is the change in volume. Since we have a constant pressure of 2.000 atm and we're adding 400 J of heat, we need to convert the pressure from atm to J/L, using the factor 1 atm = 101.325 J/L. This gives us a pressure of 202.65 J/L.

We know that Q = W for a constant pressure process, so:

400.0 J = 202.65 J/L × ΔV

ΔV = 400.0 J / 202.65 J/L = 1.974 L

The initial volume was 10.00 L, so the final volume (V_final) is:

V_final = 10.00 L + 1.974 L = 11.974 L

Therefore, the final volume of the gas after heating is approximately 12.00 L. The closest answer choice to this calculated value is (a) 12.00 L.

User Sidss
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