Question

Repeat the preceding problem for nitrogen molecules at 2950 K.

a) (a) > (b) > (c)
b) (a) = (b) = (c)
c) (c) > (b) > (a)
d) (b) > (a) > (c)

Answer 1

The average speed of nitrogen molecules at 2950 K will be greater than at previous temperatures.

Step-by-step explanation:

The question is asking to repeat the previous problem for nitrogen molecules at a temperature of 2950 K. To determine the order of (a), (b), and (c), we need to analyze the average speeds of the different molecules. At higher temperatures, the average speed of gas molecules increases. Therefore, (a) > (b) > (c), indicating that the average speed of nitrogen molecules at 2950 K will be greater than at previous temperatures.