Question

When a gas undergoes a quasi-static isobaric change in volume from 10.0 to 2.0 L, 15 J of work from an external source is required. What is the pressure of the gas?

(a) 1.5 atm
(b) 2.0 atm
(c) 2.5 atm
(d) 3.0 atm

Answer 1

The pressure of the gas is 1.5 atm.

Step-by-step explanation:

In this problem, we have an isobaric (constant pressure) change in volume from 10.0 to 2.0 L, and 15 J of external work is done on the gas. The work done on a gas can be calculated using the formula W = P * (V2 - V1), where P is the pressure and V1 and V2 are the initial and final volumes respectively.

Substituting the given values, we have 15 J = P * (2.0 - 10.0). Solving for P, we get P = 1.5 atm. Therefore, the pressure of the gas is 1.5 atm, which corresponds to option (a).