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A gas at a pressure of 2.00 atm undergoes a quasi-static isobaric expansion from 3.00 to 5.00 L. How much work is done by the gas?

(a) 10 J
(b) 20 J
(c) 30 J
(d) 40 J

User PedroD
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1 Answer

3 votes

Final answer:

The work done by the gas in the quasi-static isobaric expansion is 405.2 J.

Step-by-step explanation:

To calculate the work done by a gas in a quasi-static isobaric expansion, we can use the formula:

Work = pressure * change in volume

Given:

  • Pressure = 2.00 atm
  • Change in volume = 5.00 L - 3.00 L = 2.00 L

Substituting the values into the formula, we get:

Work = 2.00 atm * 2.00 L = 4.00 atm * L

Since the units of work are Joules (J), we need to convert atm * L to J. Using the conversion factor 1 atm = 101.3 J/L, we can calculate:

Work = 4.00 atm * L * 101.3 J/L = 405.2 J

Therefore, the work done by the gas is 405.2 J. None of the given options (a) 10 J, (b) 20 J, (c) 30 J, or (d) 40 J, are correct. The correct answer is not listed.

User Lenore
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