Question

A sample of neon gas (Ne, molar mass M=20.2g/mol) at a temperature of 13.0°C is put into a steel container of mass 47.2 g that’s at a temperature of −40.0°C. The final temperature is −28.0°C. (No heat is exchanged with the surroundings, and you can neglect any change in the volume of the container.) What is the mass of the sample of neon?

(a) 25.6 g
(b) 31.2 g
(c) 38.7 g
(d) 42.1 g

Answer 1

The mass of the neon sample is 0 g, so none of the given options are correct.

Step-by-step explanation:

To find the mass of the neon sample, we can use the equation for heat transfer between two substances:

q = mcΔT

Where q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

In this case, there is no heat exchanged with the surroundings, so the heat transferred is zero. Therefore, we can rearrange the equation to solve for the mass:

m = 0 / (cΔT)

Since the volume of the container is neglected, the specific heat capacity doesn't affect the calculation.

Substituting the values:

m = 0 / (20.2 g/mol * (-28.0 °C - (-40.0 °C)))

Simplifying:

m = 0 / (20.2 g/mol * 12.0 °C)

The answer is 0 g, which means there is no mass of the neon sample. Therefore, none of the given options (a) 25.6 g, (b) 31.2 g, (c) 38.7 g, or (d) 42.1 g are correct.