Final answer:
To calculate the number of moles of air in the lungs, we can use the ideal gas law, which relates the variables of pressure, volume, number of moles, gas constant, and temperature.
Plugging in the given values, we can calculate that there are approximately 1.99 moles of air in the 2.00-L volume of air in the lungs of the average person.
Step-by-step explanation:
To calculate the number of moles in the 2.00-L volume of air in the lungs of the average person, we can use the ideal gas law. The ideal gas law states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
We can rearrange the equation to solve for n: n = PV / RT. Since we are given the volume (2.00 L), temperature (37.0°C or 310.15 K), and the ideal gas constant (0.0821 L·atm / mol·K), we can plug in these values to calculate the number of moles.
n = (1.0 atm) * (2.00 L) / (0.0821 L·atm / mol·K) * 310.15 K = 1.99 moles
Therefore, there are approximately 1.99 moles of air in the 2.00-L volume of air in the lungs of the average person.