Final answer:
Using Gay-Lussac's Law and converting temperatures to Kelvin, the gauge pressure in the tires when the temperature drops to -40.0°C is calculated to be approximately 1.89 × 10^5 N/m². This result is not reflected in the answer choices provided, indicating a potential error in the question's options or the calculation.
Step-by-step explanation:
To solve for the gauge pressure in the tires at a lower temperature, we can use the combined gas law, which relates pressure, volume, and temperature of a gas. However, since the volume of the tires does not change, we can use a simplified version of the law that relates only pressure and temperature, commonly referred to as Gay-Lussac's Law:
P1/T1 = P2/T2
Where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature. Remember to convert temperatures to Kelvin:
T1 = 35.0°C + 273.15 = 308.15 K
T2 = -40.0°C + 273.15 = 233.15 K
We are given P1 as 2.50 × 10^5 N/m² and need to solve for P2, so we rearrange the equation to solve for P2:
P2 = P1 × (T2/T1)
P2 = 2.50 × 10^5 N/m² × (233.15 K / 308.15 K)
Calculating P2, we find that the gauge pressure in Alaska would be:
P2 = 2.50 × 10^5 N/m² × (0.7565)
P2 ≈ 1.89 × 10^5 N/m²
This is not one of the answer choices provided, suggesting a possible mistake in the options given or in the calculation. This can happen if temperatures are not correctly converted to Kelvin or if a rounding error occurs. It's important to double-check calculations and ensure that the proper formulae and conversions are used.