Final answer:
The energy required to melt a 3.50-kg bag of ice is calculated using the latent heat of fusion and then divided by the number of seconds in a day to find the average power in watts. The calculation yields approximately 13.53 W, which does not match the provided options.
Step-by-step explanation:
To determine the average power in watts entering the ice, we need to calculate the energy needed to melt the 3.50-kg bag of ice and then divide this energy by the time taken for the process, which is one day. The latent heat of fusion for ice (the amount of heat needed to melt ice without changing its temperature) is approximately 334,000 J/kg at 0°C. Therefore, the energy required to melt 3.50 kg of ice is:
Energy = mass × latent heat of fusion = 3.50 kg × 334,000 J/kg = 1,169,000 J
To find the power in watts, we consider that 1 watt = 1 joule/second and that there are 86,400 seconds in one day:
Power = Energy / Time = 1,169,000 J / 86,400 s ≈ 13.53 W
Given the options provided, none of them match the calculation. Therefore, there may be an error in the options or in the interpretation of the question.