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Four moles of a monatomic ideal gas in a cylinder at 27°C is expanded at constant pressure equal to 1 atm until its volume doubles.

(a) What is the change in internal energy?
(b) How much work was done by the gas in the process?
(c) How much heat was transferred to the gas?

User Leebriggs
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Final answer:

In an isobaric process, the change in internal energy can be calculated using the equation ΔU = nc_vΔT, the work done can be calculated using the equation W = PΔV, and the heat transferred can be calculated using the equation ΔQ = ΔU + W.

Step-by-step explanation:

In an isobaric process, the pressure of the gas remains constant while the volume changes. To calculate the change in internal energy, we can use the equation:

ΔU = nc_vΔT

where ΔU is the change in internal energy, n is the number of moles of gas, c_v is the molar specific heat at constant volume, and ΔT is the change in temperature. Since the process is isobaric, the molar specific heat at constant volume can be replaced with the molar specific heat at constant pressure, c_p.

The work done by the gas in an isobaric process can be calculated using the equation:

W = PΔV

where W is the work done, P is the pressure, and ΔV is the change in volume.

The heat transferred to the gas can be calculated using the first law of thermodynamics:

ΔQ = ΔU + W

where ΔQ is the heat transferred.

User AshtonKJ
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