Final answer:
The zeros of the function f(x)=9(x+13)^2(x-8)^2(x-6)^3 are x = -13, x = 8, and x = 6 with multiplicities 1, 1, and 3 respectively.
Step-by-step explanation:
The zeros of the function f(x)=9(x+13)^2(x-8)^2(x-6)^3 can be determined by setting the function equal to zero and solving for x.
Zero(s) of multiplicity one: x = -13, x = 8
Zero(s) of multiplicity two: none
Zero(s) of multiplicity three: x = 6