Question

What is the radius, in angstroms, of the orbital of an electron with n = 8 in a hydrogen atom?

a) 0.54 Å
b) 1.09 Å
c) 2.18 Å
d) 8.72 Å

Answer 1

The radius of an electron's orbital with n=8 in a hydrogen atom is 33.824 Å.

Step-by-step explanation:

The radius of an electron's orbital with n=8 in a hydrogen atom can be calculated using the formula:

r = aB * n2

Where r is the radius, aB is the Bohr radius, and n is the principal quantum number. For hydrogen, the Bohr radius is approximately 0.529 Å. Plugging in the values, we get:

r = 0.529 Å * 82 = 33.824 Å

Therefore, the correct answer is (d) 8.72 Å.