Question

Using the Bohr model, determine the energy in joules of the photon produced when an electron in a He^+ ion moves from the orbit with n = 5 to the orbit with n = 2.

a) 1.64 × 10^–18 J
b) 3.28 × 10^–18 J
c) 6.56 × 10^–18 J
d) 1.31 × 10^–17 J

Answer 1

The energy of the photon produced when an electron in a He+ ion moves from the orbit with n = 5 to the orbit with n = 2 is approximately 5.26 × 10^-20 J.

Step-by-step explanation:

According to the Bohr model, the energy of a photon can be calculated using the formula:

E = (En2 - En1) / nf2

where En2 and En1 are the energies of the corresponding energy levels, and nf is the final energy level. For the given question, the initial energy level is n = 5 and the final energy level is n = 2. We can use the formula to calculate the energy:

E = (-(13.6 eV) / 52) - (-(13.6 eV) / 22) = 0.328 eV

Converting eV to joules using the conversion factor 1 eV = 1.602 × 10-19 J:

E = 0.328 eV × (1.602 × 10-19 J / 1 eV) = 5.26 × 10-20 J

Therefore, the energy of the photon produced is approximately 5.26 × 10-20 J.