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What is the density of a woman who floats in fresh water with 4.00% of her volume above the surface?

a) 960 kg/m^3
b) 1040 kg/m^3
c) 1000 kg/m^3
d) 1024 kg/m^3

1 Answer

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Final answer:

The density of a woman who floats in fresh water with 4.00% of her volume above the surface is 1024 kg/m³.

Step-by-step explanation:

The formula for density is:

Density = Mass / Volume

In this case, we can find the density of the woman by comparing the volume of water she displaces when floating and when held under water. Since 4.00% of her volume is above the surface, the remaining 96.00% is submerged. We can use the concept of buoyancy to find the density:

  1. Volume submerged when floating = 96.00% of total volume

  2. Volume submerged when held under water = total volume - volume displaced when floating

  3. Volume displaced when floating = Volume submerged when floating - volume above the surface

Using these values, we can calculate the density of the woman.

Answer: d) 1024 kg/m³

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