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What pressure is exerted on the bottom of a gas tank that is 0.500-m wide and 0.900-m long and can hold 50.0 kg of gasoline when full?

a) 109 Pa
b) 218 Pa
c) 327 Pa
d) 436 Pa

1 Answer

2 votes

Final answer:

The pressure exerted on the bottom of the gas tank can be calculated by dividing the weight of the gasoline by the area of the bottom of the tank. The correct answer is approximately 1088.89 Pa.

Step-by-step explanation:

The pressure exerted on the bottom of the gas tank can be calculated by dividing the weight of the gasoline by the area of the bottom of the tank. The weight of the gasoline can be calculated by multiplying its mass by the acceleration due to gravity. The area of the bottom of the tank can be calculated by multiplying its width and length.

Given that the tank can hold 50.0 kg of gasoline, the weight of the gasoline is (50.0 kg) x (9.8 m/s^2) = 490 N. The area of the bottom of the tank is (0.500 m) x (0.900 m) = 0.45 m^2. Therefore, the pressure exerted on the bottom of the tank is 490 N / 0.45 m^2 = 1088.89 Pa.

Since none of the given options match the calculated value, none of the provided answer choices are correct. The correct answer should be approximately 1088.89 Pa.

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