Question

The approximate minimum daily dietary requirement of the amino acid leucine, C6H13NO2, is 1.1 g. What is this requirement in moles?

a) 0.009 moles

b) 0.018 moles

c) 0.027 moles

d) 0.036 moles

Answer 1

The daily dietary requirement of 1.1 g of leucine translates to about 0.00838 moles based on its molar mass of 131.17 g/mol. The closest provided answer is (a) 0.009 moles.

Step-by-step explanation:

To calculate the minimum daily dietary requirement of the amino acid leucine, C6H13NO2, in moles, we need to use the molar mass of leucine. The molar mass of leucine is approximately 131.17 g/mol. By dividing the mass requirement of leucine in grams by its molar mass, we can find the requirement in moles.

Here’s the calculation:

1. Find the molar mass of leucine: C6H13NO2 has a molar mass of 131.17 g/mol. (Carbon: 12.01 g/mol, Hydrogen: 1.01 g/mol, Nitrogen: 14.01 g/mol, Oxygen: 16.00 g/mol)
2. Calculate the moles: Divide the daily requirement by the molar mass: 1.1 g ÷ 131.17 g/mol.
3. The calculation yields approximately 0.00838 moles of leucine.

To answer the student's question, the approximate minimum daily dietary requirement of the amino acid leucine, C6H13NO2, is 1.1 g, which corresponds to about 0.00838 moles. Among the options provided, the closest answer is (a) 0.009 moles.