Question

A 567-g empty iron kettle is put in a hot stove the kettle absorbs 18,100 j of heat to raise its temperature from 15.0c to a final temperature what is the final temperature? The specific heat capacity of iron is 470j/kg•k

Answer 1

T2 = 355.92 Kelvin or 82.92°C

Step-by-step explanation:

Given the following data;

Mass = 567g to kilograms = 567/1000 = 0.567 kg

Quantity of heat = 18,100J

Initial temperature = 15°C to Kelvin = 15 + 273 = 288K

Specific heat capacity of iron = 470j/kg•k

To find the final temperature;

Heat capacity is given by the formula;

`Q = mcdt`

Where;

• Q represents the heat capacity or quantity of heat.
• m represents the mass of an object.
• c represents the specific heat capacity of water.
• dt represents the change in temperature.

Making dt the subject of formula, we have;

`dt = \frac {Q}{mc}`

Substituting into the equation, we have;

`dt = \frac {18100}{0.567*470}`

`dt = \frac {18100}{266.49}`

dt = 67.92K

Now, the final temperature T2 is;

But, dt = T2 - T1

T2 = dt + T1

T2 = 67.92 + 288

T2 = 355.92 Kelvin or 82.92°C