Question

An airplane of mass 4.0×104kg flies horizontally at an altitude of 10 km with a constant speed of 250 m/s relative to Earth. What is the magnitude of the airplane’s angular momentum relative to a ground observer directly below the plane?

a) 1.0 × 10^11 kg.m/s
b) 2.5 × 10^12 kg.m/s
c) 1.0 × 10^13 kg.m/s
d) 2.5 × 10^14 kg.m/s

Answer 1

The magnitude of the airplane's angular momentum relative to a ground observer directly below the plane is 1.0 × 10^11 kg·m/s.

Step-by-step explanation:

The magnitude of the airplane's angular momentum relative to a ground observer directly below the plane can be calculated using the formula:

Angular momentum = mass × velocity × altitude

Plugging in the given values, we get: Angular momentum = (4.0 × 10^4 kg) × (250 m/s) × (10,000 m) = 1.0 × 10^11 kg·m/s

Therefore, the magnitude of the airplane's angular momentum is 1.0 × 10^11 kg·m/s. So the correct answer is (a).