Question

A 0.2-kg particle is traveling along the line y=2.0m with a velocity 5.0m/s. What is the angular momentum of the particle about the origin?

a) 0.5 kg·m^2/s
b) 1.0 kg·m^2/s
c) 1.5 kg·m^2/s
d) 2.0 kg·m^2/s

Answer 1

The angular momentum of a particle traveling along the line y = 2.0 m with a velocity of 5.0 m/s about the origin is 2.0 kg·m^2/s.

Step-by-step explanation:

The angular momentum of a particle is given by the product of its mass, velocity, and distance from the point of reference. In this case, the particle has a mass of 0.2 kg and is traveling along the line y = 2.0 m with a velocity of 5.0 m/s.

To find the angular momentum, we need to determine the distance from the origin. Since the particle is traveling along the line y = 2.0 m, the distance from the origin is 2.0 m.

Therefore, the angular momentum of the particle about the origin is given by:

Angular Momentum = mass * velocity * distance

Angular Momentum = 0.2 kg * 5.0 m/s * 2.0 m = 2.0 kg·m^2/s

So, the angular momentum of the particle about the origin is 2.0 kg·m^2/s. Therefore, the correct answer is d) 2.0 kg·m^2/s.