Question

Calculate the angular momentum of the ice skater spinning at 6.00 rev/s given his moment of inertia is 0.400 kg·m^2.

a) 2.4 kg·m^2/s
b) 4.8 kg·m^2/s
c) 7.2 kg·m^2/s
d) 9.6 kg·m^2/s

Answer 1

The angular momentum of the ice skater spinning at 6.00 rev/s is 2.4 kg·m²/s.

Step-by-step explanation:

The angular momentum of an object can be calculated by multiplying its moment of inertia by its angular velocity. In this case, the ice skater's moment of inertia is given as 0.400 kg·m² and his angular velocity is 6.00 rev/s.

The formula for angular momentum is:

Angular momentum = Moment of inertia x Angular velocity

Substituting the given values, we have:

Angular momentum = 0.400 kg·m² x 6.00 rev/s = 2.4 kg·m²/s

Therefore, the angular momentum of the ice skater spinning at 6.00 rev/s is 2.4 kg·m²/s.