Final answer:
The east component of the hockey puck's momentum remains unchanged at 1.5 kg·m/s due to the absence of forces in that direction. The north component is found by calculating the impulse, which equals the force applied (5 N) times the time interval (1.5 s), resulting in a north component of 7.5 Ns. Therefore, the correct answer is option (d).
Step-by-step explanation:
To find the momentum of the hockey puck in both the east and north directions after a force is applied, we will apply the principles of Newton's second law and the definition of momentum (momentum = mass × velocity).
The initial momentum of the puck due east can be calculated by multiplying its mass and its initial velocity, due east:
- Initial momentum = (0.150 kg) × (10 m/s) = 1.5 kg·m/s due east.
Since there is no force in the east/west direction and the surface is frictionless, this component of the momentum remains constant throughout the 1.5 seconds.
Therefore, the east component of momentum remains at 1.5 kg·m/s.
To find the north component, we need to calculate the change in momentum due to the northward force:
- Impulse = Force × Time = (5 N) × (1.5 s) = 7.5 N·s
Since impulse is the change in momentum and the puck initially had no momentum going north, the north component of momentum after the interval is simply the impulse, which is 7.5 N·s.
In conclusion, the momentum components at the end of the 1.5-s interval are:
- North component: 7.5 Ns
- East component: 1.5 Ns
Hence, option (d) North component: 7.5 Ns; East component: 1.5 Ns is the correct answer.