Question

A 30.0-g ice cube at its melting point is dropped into an aluminum calorimeter of mass 100.0 g in equilibrium at 24.0°C with 300.0 g of an unknown liquid. The final temperature is 4.0°C. What is the heat capacity of the liquid?

a) 0.50 J/g°C

b) 1.00 J/g°C

c) 2.00 J/g°C

d) 4.00 J/g°C

Answer 1

To find the heat capacity of the liquid, we need to determine the amount of heat transferred from the ice cube to the liquid. This can be done by calculating the heat absorbed by the ice cube and the heat absorbed by the liquid using the equations for heat transfer. By equating the two equations, we can solve for the specific heat capacity of the liquid.

Step-by-step explanation:

To find the heat capacity of the liquid, we need to determine the amount of heat transferred.

First, we calculate the heat absorbed by the ice cube using the equation:

Q = mcΔT

Where Q is the heat absorbed, m is the mass of the ice cube, c is the specific heat capacity of ice, and ΔT is the change in temperature.

Next, we calculate the heat absorbed by the liquid using the equation:

Q = mcΔT

where Q is the heat absorbed, m is the mass of the liquid, c is the specific heat capacity of the liquid, and ΔT is the change in temperature.

Finally, the heat absorbed by the liquid would be equal to the heat transferred from the ice cube. Therefore, we can equate the two equations and solve for the specific heat capacity of the liquid.