Question

The mass of Earth is 5.97×1024 kg and its orbital radius is an average of 1.50×1011 m. Calculate the magnitude of its linear momentum at the location in the diagram.

a) 8.96×1035 kg·m/s
b) 1.49×1035 kg·m/s
c) 4.48×1035 kg·m/s
d) 2.99×1035 kg·m/s

Answer 1

To calculate the linear momentum of Earth, you need to know its velocity, which can be determined using the formula for the circumference of a circle. However, since the period of Earth's orbit is not provided, the correct answer cannot be determined.

Step-by-step explanation:

To calculate the linear momentum of Earth, we can use the formula:

p = mv

where p is the linear momentum, m is the mass, and v is the velocity.

Since Earth is in orbit, its velocity can be determined using the formula for the circumference of a circle:

v = 2πr/T

where v is the velocity, r is the radius, and T is the period (time taken for one complete orbit).

Given the mass of Earth as 5.97×10^24 kg and its orbital radius as 1.50×10^11 m, we can calculate the velocity:

v = 2π(1.50×10^11 m) / T

However, the period of Earth's orbit is not provided, so we cannot calculate the precise velocity and linear momentum. Therefore, the correct answer cannot be determined from the given information.