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Verify the normalization equation ∫[infinity]0f(v)dv=1. In doing the integral, first make the substitution u=√m/2kBTv=vv_p. This "scaling" transformation gives you all features of the answer except for the integral, which is a dimensionless numerical factor. You’ll need the formula

a) Verify the normalization equation for the probability distribution.
b) The integral is unsolvable without numerical values.
c) The substitution is unnecessary for the solution.
d) Normalization is valid only for ideal gases.

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Final answer:

To verify the normalization equation ∫[infinity]0f(v)dv=1, make the substitution u=√m/2kBTv=vv_p. This substitution is necessary to transform the integral and obtain a dimensionless numerical factor. The normalization equation is valid for any probability distribution, not just ideal gases.

Step-by-step explanation:

To verify the normalization equation ∫[infinity]0f(v)dv=1, we can make the substitution u=√m/2kBTv=vv_p.

This substitution is necessary to transform the integral and obtain a dimensionless numerical factor.

The normalization equation is valid for any probability distribution, not just ideal gases.

Therefore, the correct answer is a) Verify the normalization equation for the probability distribution.

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