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Ten narrow slits are equally spaced 0.25 mm apart and illuminated with yellow light of wavelength 580 nm.

(a) What are the angular positions of the third and fourth principal maxima?
(b) What is the separation of these maxima on a screen 2.0 m from the slits?

User Queena
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Final answer:

The angular positions of the third and fourth principal maxima are approximately 0.4427° and 0.5903°, respectively. The separation of these maxima on a screen 2.0 m from the slits is approximately 4.64 cm.

Step-by-step explanation:

To find the angular positions of the third and fourth principal maxima, we can use the formula for the angle of the principal maxima in a multiple-slit interference pattern:

sin(θn) = nλ / d

where θn is the angle of the nth principal maximum, n is the order of the maximum, λ is the wavelength of the light, and d is the separation between the slits. For the third principal maximum, n = 3, so:

sin(θ3) = (3 * 580 nm) / 0.25 mm

Solving for θ3, we find that θ3 ≈ 0.4427°. Similarly, for the fourth principal maximum, n = 4:

sin(θ4) = (4 * 580 nm) / 0.25 mm

Which yields θ4 ≈ 0.5903°.

To find the separation of these maxima on a screen 2.0 m from the slits, we can use the formula for the separation of the principal maxima:

y = (λL) / d

where y is the separation of the maxima on the screen, L is the distance between the slits and the screen, and d is the separation between the slits. Plugging in the values, we get:

y = (580 nm * 2.0 m) / 0.25 mm

Which gives us y ≈ 4.64 cm.

User MrDracow
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