Final answer:
To find the wavelength of light that has its third minimum at an angle of 48.6° when it falls on a single slit of width 3.00μm, we can use the formula for the location of the minima in a single-slit diffraction pattern..
Step-by-step explanation:
To find the wavelength of light that has its third minimum at an angle of 48.6° when it falls on a single slit of width 3.00μm, we can use the formula for the location of the minima in a single-slit diffraction pattern. The formula is given by: sin(θ) = (m * λ) / w, where θ is the angle, m is the order of the minimum, λ is the wavelength of light, and w is the width of the slit.
In this case, we are looking for the third minimum, so m = 3. We know the angle θ = 48.6° and the width of the slit w = 3.00μm. To find the wavelength λ, we rearrange the formula and solve for it:
λ = (w * sin(θ)) / m
Plugging in the values, we have λ = (3.00μm * sin(48.6°)) / 3.