Final answer:
The wavelength of light falling on double slits separated by 2.00 µm with the third-order maximum at an angle of 60.0° is 1.15 µm.
Step-by-step explanation:
To find the wavelength of light falling on double slits, we can use the formula:
λ = (2 * d * sinθ) / N
Where:
- λ is the wavelength
- d is the separation between the double slits (2.00 µm)
- θ is the angle of the third-order maximum (60.0°)
- N is the order of the maximum
Plugging in the given values:
λ = (2 * 2.00 µm * sin(60.0°)) / 3
Simplifying the equation:
λ = 1.15 µm
Therefore, the wavelength of light falling on double slits separated by 2.00 µm with the third-order maximum at an angle of 60.0° is 1.15 µm.