Question

A point source of light is 50 cm in front of a converging lens of focal length 30 cm. A concave mirror with a focal length of 20 cm is placed 25 cm behind the lens. Where does the final image form, and what are its orientation and magnification?

Answer 1

The final image forms behind the concave mirror, at a distance of 17.14 cm. The image is virtual, upright, and has a magnification of approximately -0.686.

Step-by-step explanation:

In this situation, the final image forms behind the concave mirror. To determine the location, orientation, and magnification of the final image, we can use the lens and mirror formula:

1/f = 1/v - 1/u

Where f is the focal length, v is the image distance, and u is the object distance.

Using the given values, the object distance (u) is -25 cm, the focal length of the concave mirror (f) is -20 cm, and the distance between the lens and the mirror is -25 cm.

Plugging these values into the lens and mirror formula, we can calculate the image distance (v).

The final image forms at a distance of 17.14 cm behind the concave mirror. Since the object is in front of the lens, the image formed by the mirror is virtual and upright. The magnification of the image can be calculated using the formula: magnification = - v/u.

Substituting the values, the magnification is approximately -0.686.