Final answer:
The percent yield of water in the lab, given an actual yield of 1.15 moles of water and a theoretical yield based on a one-to-one stoichiometry with 2.25 moles of calcium hydroxide used, would be 51.11%.
Step-by-step explanation:
To calculate the percent yield of water, you need to start by knowing the theoretical yield and the actual yield of the water produced in the reaction. The reaction in question is likely the decomposition of calcium hydroxide, which can be represented by a balanced chemical equation that includes water as a product. The percent yield is then found using the formula:
Percent Yield = (Actual Yield / Theoretical Yield) × 100%
Since the actual yield is 1.15 moles of water and the number of moles of calcium hydroxide used is 2.25 moles, you would determine the theoretical yield based on the stoichiometry of the balanced reaction. Since the stoichiometry isn't provided here, we'll assume it's a one-to-one ratio for simplicity. Thus, the theoretical yield would also be 2.25 moles of water. The percent yield is calculated as:
Percent Yield = (1.15 mol / 2.25 mol) × 100% = 51.11%
The percent yield of water in this lab would therefore be 51.11%.