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A sick drawer contains: 3 navy socks, 4 gray socks, and 3 black socks. Mandy randomly selects two socks, one at a time and does not replace them. What is the probability that’s the first sock Mandy selects will be gray and the second sock will be navy?

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Final answer:

The probability that the first sock Mandy selects will be gray and the second sock will be navy is 2/15.

Step-by-step explanation:

To find the probability that the first sock Mandy selects will be gray and the second sock will be navy, we need to first determine the total number of socks and the number of possible outcomes.

There are a total of 3 navy socks, 4 gray socks, and 3 black socks, so the total number of socks is 3 + 4 + 3 = 10.

When Mandy selects the first sock, there are 10 socks to choose from and 4 gray socks. Therefore, the probability that the first sock she selects will be gray is 4/10.

After Mandy selects the first sock, there are 9 socks remaining, and 3 navy socks. So the probability that the second sock she selects will be navy is 3/9.

To find the probability of both events happening together, we multiply the probabilities: (4/10) * (3/9) = 2/15.

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