Final answer:
The intensities of the three interference peaks in the central maximum of a diffraction pattern require calculations using the double slit interference formula and the Fraunhofer diffraction equations, given the light's wavelength, slit width, and slit separation.
Step-by-step explanation:
The question asks to calculate the intensities of three interference peaks other than the central peak in the central maximum of the diffraction pattern produced by light incident on a double slit. The given parameters are a light wavelength of 500 nm, slit width of 1000 nm, and slit separation of 1500 nm. The central spot's intensity is given as 1 mW/cm². The intensities of other peaks can be calculated using the double slit interference formula, though an exact calculation would require additional information such as the distance to the screen and the formula for intensity distribution, which typically involves the square of the amplitude of the wave function.
The interference pattern can be determined by the equation d sin(θ) = mλ, where d is the slit separation, θ is the angle of the peak, m is the order of the maxima, and λ is the wavelength of the light. However, to calculate the relative intensities of these maxima in comparison to the central maximum, the Fraunhofer diffraction equations would be necessary, which involve both the slit width and separation in conjunction with the distance to the observation screen.