Question

Young’s double-slit experiment is performed immersed in water (n=1.333). The light source is a He-Ne laser, λ=632.9nm in vacuum.

(a) What is the wavelength of this light in water?

Answer 1

The wavelength of the He-Ne laser light in water with a refractive index of 1.333 is 474.6 nm.

Step-by-step explanation:

The wavelength of light changes when it travels from one medium to another. In water with a refractive index (n) of 1.333, the wavelength of the He-Ne laser light (λ) with a wavelength of 632.8 nm in vacuum can be calculated using the formula:

λ = λo/n

where λo is the wavelength in vacuum and n is the medium's index of refraction.

Substituting the values, we get:

λ = 632.8 nm / 1.333 = 474.6 nm