Question

How much work does a supermarket checkout attendant do on a can of soup he pushes 0.600 m horizontally with a force of 5.00 N?

a) 2.00 J
b) 3.00 J
c) 4.00 J
d) 5.00 J

Answer 1

The work done by the checkout attendant on the can of soup is calculated by multiplying the force applied by the distance the can is pushed. Since the work is done horizontally, it equates to 3.00 J.

Step-by-step explanation:

To calculate the work done by a supermarket checkout attendant on a can of soup, we can use the formula for work W = F × d × cos(θ), where W is work, F represents the force applied, d is the displacement, and θ is the angle between the force vector and the displacement vector. Since the force is applied horizontally and the can is pushed horizontally, the angle θ is 0 degrees and cos(0) is 1. Therefore, the work done on the can of soup is W = 5.00 N × 0.600 m × 1.

Calculating the work done, we get:

W = 5.00 N × 0.600 m = 3.00 J

So, the correct answer to the question is (b) 3.00 J.