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A toy cart is pulled a distance of 6.0 m in a straight line across the floor. The force pulling the cart has a magnitude of 20 N and is directed at 37° above the horizontal. What is the work done by this force?

a) 60 J
b) 80 J
c) 90 J
d) 100 J

1 Answer

3 votes

Final answer:

The work done by a 20 N force at a 37° angle over 6.0 m is calculated by finding the horizontal force component and then multiplying by distance, which roughly equates to 90 J when rounded.

Step-by-step explanation:

The work done on an object is calculated using the formula Work = Force × Distance × cos(ϴ), where ϴ is the angle between the force direction and the displacement direction. In this case, we are given a force of 20 N at an angle of 37° above the horizontal, and the displacement is 6.0 m along the horizontal.

We need to calculate the horizontal component of the force because work is only done by the component of the force in the direction of displacement. The horizontal component is calculated as F×cos(ϴ), which is 20 N × cos(37°). Then, we use this horizontal component to calculate the work done:

Work = (20 N × cos(37°)) × (6.0 m)

Plugging into our calculators, we get:

Work = (20 N × 0.7986) × (6.0 m) = 95.832 J

The work done by the 20 N force over the 6.0 m distance with a 37° angle is approximately 96 J which most closely matches option (c) 90 J after rounding to the nearest tenth.

User Mohammad Emran
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