Final answer:
The net external force exerted on a 1100.0-kg artillery shell with an acceleration of 2.40×104 m/s² is 2.64 × 107 N. By Newton's third law, the ship experiences a reaction force of the same magnitude, 2.64 × 107 N.
Step-by-step explanation:
For question (a), we calculate the net external force exerted on the artillery shell using Newton's second law, which states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration (F = m × a). In this case, the mass of the artillery shell (m) is 1100.0 kg, and the acceleration (a) is 2.40×104 m/s². The calculation is as follows:
F = m × a = 1100.0 kg × 2.40×104 m/s² = 2.64 × 107 N.
Therefore, the net external force exerted on the shell is 2.64 × 107 N.
The net external force exerted on the artillery shell can be calculated using Newton's second law, which states that force (F) equals mass (m) multiplied by acceleration (a). In this case, the mass of the artillery shell is 1100.0 kg and its acceleration is 2.40x10^4 m/s². Therefore, the net external force is 2.64x10^7 N (newtons).
The magnitude of the force exerted on the ship by the artillery shell is also 2.64x10^7 N. This is because of Newton's third law, which states that every action has an equal and opposite reaction. When the artillery shell is fired from the battleship, it exerts a force on the ship in the opposite direction.
For question (b), according to Newton's third law of motion, every action has an equal and opposite reaction. This means that the magnitude of the force exerted on the ship by the artillery shell is equal to the force exerted on the artillery shell by the ship. Hence, the magnitude of the reaction force on the ship is also 2.64 × 107 N.