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Cam Newton of the Carolina Panthers throws a perfect football spiral at 8.0 rev/s. The radius of a pro football is 8.5 cm at the middle of the short side. What is the centripetal acceleration of the laces on the football?

a) 34.0 m/s²
b) 68.0 m/s²
c) 85.0 m/s²
d) 136.0 m/s²

1 Answer

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Final answer:

To calculate the centripetal acceleration of the laces on a football thrown in a spiral by Cam Newton, the angular velocity is first converted to rad/s, and then the centripetal acceleration formula is applied. The acceleration is found to be approximately 34.0 m/s².

Step-by-step explanation:

The question asks to calculate the centripetal acceleration of the laces on a football thrown in a spiral. Cam Newton throws the football at a rate of 8.0 revolutions per second (rev/s), and the radius of the football is given as 8.5 cm.

To find the centripetal acceleration, we first need to convert the angular velocity from rev/s to radians per second (rad/s) since 1 rev = 2π rad. Therefore, the angular velocity (ω) is 8.0 rev/s × 2π rad/rev = 16π rad/s.

Next, we use the formula for centripetal acceleration, ac = ω2 × r, where r is the radius of the circular path.

Converting 8.5 cm to meters (0.085 m), we get ac = (16π rad/s)2 × 0.085 m = 108.8π2 m/s². When calculated, this gives a centripetal acceleration of approximately 34.0 m/s², which corresponds to option (a).

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