Question

The position of a particle changes from →r1=(2.0​ˆi+3.0ˆj)cm to →r2=(−4.0ˆi+3.0ˆj)cm. What is the particle’s displacement?

a) Option a: Δ→r = (-6.0ˆi + 0ˆj) cm; Option b: Δ→r = (6.0ˆi + 0ˆj) cm
b) Option a: Δ→r = (2.0ˆi - 3.0ˆj) cm; Option b: Δ→r = (-6.0ˆi - 3.0ˆj) cm
c) Option a: Δ→r = (6.0ˆi + 0ˆj) cm; Option b: Δ→r = (-6.0ˆi + 0ˆj) cm
d) Option a: Δ→r = (-6.0ˆi - 3.0ˆj) cm; Option b: Δ→r = (2.0ˆi - 3.0ˆj) cm

Answer 1

The particle's displacement is -6.0 î + 0 ĵ cm.

Step-by-step explanation:

The displacement of a particle is the change in its position from one point to another. To find the particle's displacement, we subtract the initial position vector from the final position vector. In this case, the initial position vector is (2.0 î + 3.0 ĵ) cm and the final position vector is (-4.0 î + 3.0 ĵ) cm.

Δ→r = (-4.0 î + 3.0 ĵ) cm - (2.0 î + 3.0 ĵ) cm

Δ→r = -6.0 î + 0 ĵ cm,

Therefore, the particle's displacement is option a: Δ→r = (-6.0 î + 0 ĵ) cm.