Question

A powerful motorcycle can accelerate from rest to 26.8 m/s (100 km/h) in only 3.90 s. (a) What is its average acceleration? (b) Assuming constant acceleration, how far does it travel in that time?

a) (a) 6.87 m/s²; (b) 52.4 m
b) (a) 9.20 m/s²; (b) 104 m
c) (a) 7.80 m/s²; (b) 82.3 m
d) (a) 8.00 m/s²; (b) 78.2 m

Answer 1

The average acceleration is approximately 6.87 m/s², and the motorcycle travels approximately 52.4 m in that time.

Step-by-step explanation:

a) Average acceleration:

Initial velocity, u = 0 m/s

Final velocity, v = 26.8 m/s

Time, t = 3.90 s

The average acceleration is given by the formula:

a = (v - u) / t

a = (26.8 - 0) / 3.90

a ≈ 6.87 m/s²

b) Distance traveled:

The distance traveled can be calculated using the equation:

d = ut + 0.5 at2

d = 0 + 0.5 * 6.87 * (3.90)2

d ≈ 52.4 m