Question

A very strong, but inept, shot putter puts the shot straight up vertically with an initial velocity of 11.0 m/s. How long a time does he have to get out of the way if the shot was released at a height of 2.20 m and he is 1.80 m tall?

a) 1.10 s
b) 2.20 s
c) 0.80 s
d) 3.30 s

Answer 1

The shot putter has approximately 1.10 seconds to get out of the way. Option (A) is correct.

Step-by-step explanation:

Acceleration is the rate of change of velocity. Usually, acceleration means the speed is changing, but not always. When an object moves in a circular path at a constant speed, it is still accelerating, because the direction of its velocity is changing.

To determine how long a time the shot putter has to get out of the way, we need to find the time it takes for the shot to reach a height of 1.80 m. Since the shot is thrown straight up vertically, we can use the equation:

Final Velocity = Initial Velocity + (Acceleration * Time)

At the highest point of the shot's trajectory, the final velocity is 0 m/s. The initial velocity is 11.0 m/s, and the acceleration due to gravity is -9.8 m/s^2 (negative because it acts against the motion). We can plug these values into the equation to solve for time:

0 m/s = 11.0 m/s - (9.8 m/s^2 * Time)

Simplifying the equation gives us:

Time = 11.0 m/s / 9.8 m/s^2

Calculating this gives us a time of approximately 1.10 seconds. Therefore, the shot putter has about 1.10 seconds to get out of the way.