Question

A particle moves in a straight line with an initial velocity of 30 m/s and constant acceleration 30 m/s². (a) What is its displacement at t = 5 s? (b) What is its velocity at this same time?

a) (a) 175 m, (b) 150 m/s
b) (a) 150 m, (b) 175 m/s
c) (a) 225 m, (b) 120 m/s
d) (a) 120 m, (b) 225 m/s

Answer 1

The displacement at t = 5 s is 525 m and the velocity at t = 5 s is 180 m/s.

Step-by-step explanation:

To find the displacement at t = 5 s, we can use the equation:

d = v0t + (1/2)at2

where:

• d is the displacement
• v0 is the initial velocity
• t is the time
• a is the acceleration

Plugging in the given values, we have:

d = (30 m/s)(5 s) + (1/2)(30 m/s²)(5 s)2

d = 150 m + (1/2)(30 m/s²)(25 s²)

d = 150 m + 375 m

d = 525 m

To find the velocity at t = 5 s, we can use the equation:

v = v0 + at

Plugging in the given values, we have:

v = 30 m/s + (30 m/s²)(5 s)

v = 30 m/s + 150 m/s

v = 180 m/s