Final answer:
The car travels a distance of 172.8 m in 12.0 s and has a final velocity of 28.8 m/s.
Step-by-step explanation:
(a) Draw a sketch:
(b) List the knowns in this problem: The acceleration (a) is 2.40 m/s², the time (t) is 12.0 s, the initial velocity (vo) is 0 m/s, and the initial position (xo) is 0 m.
(c) To find how far the car travels in those 12.0 s, we can use the equation x = xo + vot + 1/2at². Plugging in the values, we get x = 0 + 0 + (1/2)(2.40 m/s²)(12.0 s)² = 172.8 m.
(d) The final velocity (v) can be found using the equation v = vo + at. Plugging in the values, we get v = 0 + (2.40 m/s²)(12.0 s) = 28.8 m/s.