Question

Calculate the displacement and velocity at times of (a) 0.500 s, (b) 1.00 s, (c) 1.50 s, (d) 2.00 s, and (e) 2.50 s for a rock thrown straight down with an initial velocity of 14.0 m/s from the Verrazano Narrows Bridge in New York City. The roadway of this bridge is 70.0 m above the water.

(a) Displacement is:
a) 24.5 m
b) 49.0 m
c) 70.0 m
d) 98.0 m

(b) Displacement is:
a) 19.6 m
b) 34.0 m
c) 49.0 m
d) 70.0 m

(c) Displacement is:
a) 6.9 m
b) 19.6 m
c) 34.0 m
d) 49.0 m

(d) Displacement is:
a) -5.9 m
b) 6.9 m
c) 19.6 m
d) 34.0 m

(e) Displacement is:
a) -24.5 m
b) -5.9 m
c) 6.9 m
d) 19.6 m

Answer 1

The displacement and velocity at times from 0.500 s to 2.50 s for a rock thrown straight down with an initial velocity of 14.0 m/s from the Verrazano Narrows Bridge are calculated.

Step-by-step explanation:

To calculate the displacement and velocity at various times for a rock thrown straight down from the Verrazano Narrows Bridge, we can use the equations of motion. The initial velocity of the rock is 14.0 m/s and the height of the bridge is 70.0 m above the water.

1. At 0.500 s, the displacement is 24.5 m and the velocity is 14.0 m/s.
2. At 1.00 s, the displacement is 49.0 m and the velocity is 0 m/s.
3. At 1.50 s, the displacement is 70.0 m (the rock reaches the water) and the velocity is -14.0 m/s.
4. At 2.00 s, the displacement is 70.0 m and the velocity is -14.0 m/s.
5. At 2.50 s, the displacement is 70.0 m and the velocity is -14.0 m/s.