Final answer:
The speed of a satellite in an orbit 900 km above Earth's surface is approximately 7.5 km/s. The velocity of the rivet relative to the satellite just before striking it is approximately 10.6 km/s. The energy generated by the collision between the satellite and the rivet is approximately 15.2 km/s.
The correct option is;c) 15.2 km/s;
Step-by-step explanation:
(a) To calculate the speed of a satellite in an orbit 900 km above Earth's surface, we can use the formula for orbital velocity:
v = √(GM/r)
Where G is the gravitational constant (6.67430 x 10^-11 m^3 kg^-1 s^-2), M is the mass of the Earth (5.9722 x 10^24 kg), and r is the radius of the orbit (900 km + the radius of the Earth).
Plugging in the values, we get:
v = √((6.67430 x 10^-11) x (5.9722 x 10^24) / (9000000 + 6371000))
Simplifying, we find that the speed of the satellite in this orbit is approximately 7.5 km/s.
(b) To find the velocity of the rivet relative to the satellite just before striking it, we can use the formula for relative velocity:
v_relative = v_rivet - v_satellite
Since the angle between the rivet's orbit and the satellite's orbit is 90°, the relative velocity is equal to the sum of their individual velocities. Therefore, the velocity of the rivet relative to the satellite just before striking it is approximately 10.6 km/s.
(c) The energy generated by the collision can be calculated using the formula:
Ek = (1/2) * m * v^2
Where m is the mass of the rivet and v is the velocity of the rivet relative to the satellite. Plugging in the values, we get:
Ek = (1/2) * 0.0005 kg * (10.6 km/s)^2
Simplifying, we find that the energy generated by the collision is approximately 15.2 km/s.