Question

Suppose you start an antique car by exerting a force of 300 N on its crank for 0.250 s. What is the angular momentum given to the engine if the handle of the crank is 0.300 m from the pivot and the force is exerted to create maximum torque the entire time?

a) 22.5 Nm s
b) 33.8 Nm s
c) 45.0 Nm s
d) 56.3 Nm s

Answer 1

The angular momentum given to the engine is 22.5 Nm s.

Step-by-step explanation:

To find the angular momentum given to the engine, we can use the equation:

Angular momentum = torque x time

The torque can be calculated using the formula:

Torque = force x distance

Given that the force is 300 N, the distance is 0.300 m, and the time is 0.250 s, we can substitute these values into the equations to find the angular momentum.

Angular momentum = (force x distance) x time = (300 N x 0.300 m) x 0.250 s = 22.5 Nm s