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Calculate the angular velocity of the orbital motion of Earth around the Sun.

a) Approximately 1.99 x 10^-7 rad/s
b) Approximately 1.99 x 10^7 rad/s
c) Approximately 1.99 x 10^-4 rad/s
d) Approximately 1.99 x 10^4 rad/s

User Rororo
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1 Answer

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Final answer:

The angular velocity of Earth's orbit around the Sun is calculated using the period of one orbit, which is approximately one year. The resulting angular velocity is approximately 1.99 x 10^-7 rad/s.

Step-by-step explanation:

To calculate the angular velocity of the Earth in its orbit around the Sun, we need to know the period of one orbit, which is one year. Given that a year is approximately 365.25 days and that each day has 86400 seconds, the period T is 365.25 × 86400 s. The angular velocity, ω, is given by ω = 2π / T.

Converting days to seconds for the period T we get: T = 365.25 × 86400 s = 3.156 × 107 s. Now, calculating the angular velocity:

ω = 2π / (3.156 × 107 s) ≈ 1.99 × 10-7 rad/s

Therefore, the correct answer is a) Approximately 1.99 × 10-7 rad/s.

User Sunny Prakash
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