Final answer:
The scale reading in an elevator is greater than the person's weight when the elevator is accelerating upward.
Step-by-step explanation:
The scale reading in an elevator can be calculated by using Newton's second law, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the woman's mass is 75.0 kg and the elevator accelerates from rest to 30.0 m/s in 2.00 s. So, the scale reading can be calculated as:
Scale reading = (mass of the woman) x (acceleration of the elevator) = (75.0 kg) x (30.0 m/s^2) = 2250 N
This scale reading is greater than her weight, which can be calculated using the formula weight = mass x gravity. Her weight is:
Weight = (mass of the woman) x (acceleration due to gravity) = (75.0 kg) x (9.8 m/s^2) = 735 N
So, the scale reading is greater than her weight, which is expected because the scale exerts an upward force on her equal to its reading. It is reasonable for the scale reading to be greater than her weight when the elevator is accelerating upward.
(b) The unreasonable part about the result is that the scale reading is given as 825 N, but the calculated scale reading is 2250 N. The given scale reading is incorrect.
(c) The given premises are inconsistent because the calculated scale reading does not match the given scale reading.