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Vectors →A and →B have identical magnitudes of 5.0 units. Find the angle between them if →A+→B=5√2ˆj.

a) 45∘


b) 90∘


c) 30∘


d) 60∘

User Hai Vu
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1 Answer

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Final answer:

The angle between vectors →A and →B is 90°.

Step-by-step explanation:

To find the angle between two vectors, we can use the dot product formula: cos() = (→A · →B) / (|→A| * |→B|). Here, we're given that |→A| = |→B| = 5.0 units. We're also given that →A + →B = 5√2^j. Since →A and →B have the same magnitude and opposite directions, their sum would result in a vector that has a magnitude of 0 units. Therefore, we can conclude that the angle between →A and →B is 90°. So, the correct answer is (b) 90°.

User TJ Tang
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