Final answer:
To determine the time Burt Munro took to complete the course, we calculate the acceleration time to reach his top speed and the time spent at constant speed. The total time is the sum of both intervals, resulting in approximately 99.2 seconds, which does not match any of the given options.
Step-by-step explanation:
To calculate how long it took Burt Munro to complete the course, we first need to find out how long he accelerated until reaching his top speed of 295.38 km/h (which is approximately 82 m/s). Using the formula for acceleration (a = ∆v / t), where ∆v is the change in velocity and t is the time, we find that his acceleration rate is 24 m/s². As he reached 96 km/h (26.7 m/s) from rest (0 m/s) in 4.00 s, we use the formula for uniformly accelerated motion (v = u + at) to find the time it took to reach his top speed. The final velocity (v) is 82 m/s, initial velocity (u) is 0, acceleration (a) is 24 m/s².
Next, we calculate the acceleration phase time using v = u + at, and we get t = (v - u) / a, which results in approximately 3.42 seconds to reach 82 m/s. Now, the total distance covered during acceleration can be found using s = ut + (1/2)at², which results in a distance of 140.7 meters.
Subsequently, we calculate the distance remaining for the constant speed phase as 8.00 km (8000 meters) minus the acceleration distance, which leaves us with 7859.3 meters. Finally, to find the time to cover this distance at constant speed, we divide the remaining distance by the top speed (t = s / v), which gives us approximately 95.8 seconds.
The total time taken to complete the course is the sum of the acceleration time and the constant speed time, which results in 99.2 seconds (or approximately 1 minute 39.2 seconds). Since none of the options match this calculated time, there might be a mistake in the options or an incorrect interpretation of the given information.