Answer:
The calculated value |t| = |-3.082| =3.082 > 2.0322 at 0.05 level of significance
The null hypothesis is rejected
An alternative hypothesis is accepted
There is evidence that the machine should be stopped and production wait for repairs
Explanation:
Step(i):-
Given that the mean of the Population(μ) = 8 ounces
Given that the sample size 'n' = 35
The mean of the sample(x⁻) = 7.91
The variance of the sample S² = 0.03 ounces
S = √0.03 = 0.1732
Step(ii):-
Null Hypothesis: H₀: There is no evidence that the machine should be stopped and production wait for repairs
Alternative Hypothesis: H₁: There is evidence that the machine should be stopped and production wait for repairs
t = - 3.082
|t| = |-3.082| =3.082
Degrees of freedom
ν = n-1 = 35-1=34
t₀.₀₅ = 2.0322
The calculated value |t| = |-3.082| =3.082 > 2.0322 at 0.05 level of significance
The null hypothesis is rejected
An alternative hypothesis is accepted
conclusion:-
There is evidence that the machine should be stopped and production wait for repairs